| 林深時見鹿 |
2020-05-29 09:44 |
相位恢復算法
有會相位恢復算法的嗎？能幫我看看下面的代碼錯哪兒了嗎？不勝感激 *NlpotW,f
4V$fGjJ3
2d centered Fourier transform，居中的傅里葉變換 &K
*X)DAs
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% HIGNRm
% Citation for this code and algorithm: q^*6C[G B
% Tatiana Latychevskaia and Hans-Werner Fink PrSkHxm
% "Practical algorithms for simulation and reconstruction of digital in-line holograms", ?/'}JS(Sm
% Appl. Optics 54, 2424 - 2434 (2015) ) * TF"
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Sl>>SP
% The code is written by Tatiana Latychevskaia, 2002 j V^C19
% The version of Matlab for this code is R2010b ~@Kf2dHes
C(o.Cy6
function [out] = FT2Dc(u0); h!e2
+4{4{
.45^=2NGmQ
[Nx, Ny] = size(1i,1j); Z>2]Xx%
\
aD ESr?
f1 = zeros(Nx,Ny); HH8;J66I&
T4 r5s
for ii = 1:Nx iCrxV{
for jj = 1:Ny Uo6(|m m
f1(ii,jj) = exp(1i*pi*(ii + jj)); `c(\i$1JY)
end n +;vjVS%
end WeC(w+}p
1,`H:%z%
FT = fft2(f1.*in); hD
q2-X}
<MdGe1n
out = f1.*FT; `f)(Y1%.
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
|
|