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    [求助]相位恢復(fù)算法 [復(fù)制鏈接]

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    只看樓主 倒序閱讀 樓主  發(fā)表于: 2020-05-29
    有會(huì)相位恢復(fù)算法的嗎?能幫我看看下面的代碼錯(cuò)哪兒了嗎?不勝感激 IEvdV6{K  
    LjHVJSC  
    2d centered Fourier transform,居中的傅里葉變換 `5Zz5V  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% jZr q{Z<  
    % Citation for this code and algorithm: Eu04e N  
    % Tatiana Latychevskaia and Hans-Werner Fink he hFEyx  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", IMONgFBS  
    % Appl. Optics 54, 2424 - 2434 (2015) o*hF<D$Y  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 2^yU ~`#  
    % The code is written by Tatiana Latychevskaia, 2002 ]5:8Z@  
    % The version of Matlab for this code is R2010b @pU)_d!pJ  
    \Y}8S/]  
    function [out] = FT2Dc(u0); ^5 Tqy(M  
    d m%8K6|  
    [Nx, Ny] = size(1i,1j); <1M-Ro?5k  
    Ozf@6\/t  
    f1 = zeros(Nx,Ny); ufT`"i  
    X!g#T9kG  
    for ii = 1:Nx Jxm.cC5z.  
        for jj = 1:Ny @U}1EC{A  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); -z(+/